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Given a **graph** consisting of **N** nodes numbered from **0** to **N – 1** and **M** edges in the form of pairs **{a, b}**, the task is to find the minimum number of edges to be added to the graph such that if there exists a path from any node **a** to node **b**, then there should be paths from node **a** to nodes **[ a + 1, a + 2, a + 3, …, b – 1]** as well.

**Examples:**

_ N = 7, M = 3, Edges[][] = {{1, 5}, {2, 4}, {3, 4}} _Input:

_ 1 _Output:

Explanation:

_There is a path from 1 to 5. So there should be paths from 1 to 2, 3 and 4 as well. _

Adding an edge {1, 2} will be sufficient to reach the other two nodes of the graph.

_ N = 8, M = 3 Edges[][] = {{1, 2}, {2, 3}, {3, 4}} _Input:

_ 0 _Output:

**Recommended: Please try your approach on _ {IDE}_ first, before moving on to the solution.**

**Approach:**

The idea is to use a Disjoint Set or Union find. Each component in the disjoint set should have consecutive nodes. This can be done by maintaining *maximum_node[]* and *minimum_node[]* arrays to store the maximum and minimum value of nodes in each component respectively. Follow the steps below to solve the problem:

- Create a structure for the disjoint set union.
- Initialize the
**answer**as 0 and iterate over all the nodes in the graph to get the component of the current node.

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