# Introduction Python isfinite() Method with Examples Python isfinite() is a library method of math module, it is used to check whether a given number is a finite number of not, it accepts a number (integer/float, finite, infinite or NaN), and returns True if number neither an infinity nor a NaN (Not A Number), else it returns False.

Python isfinite() is a library method of math module, it is used to check whether a given number is a finite number of not, it accepts a number (integer/float, finite, infinite or NaN), and returns True if number neither an infinity nor a NaN (Not A Number), else it returns False.

Python isfinite()

### Syntax

``````math.isfinite(x)

``````

### Parameter(s):

• x – a number that has to be checked whether it is finite or not.

### Return value:

The isfinite() function returns two types of output:

• `True`: If the number is finite.

• `False`: If the number is not finite.

Examples of Python isfinite() method

### Example 1

``````import math
a = 6
b = 7.54
c = 8+0.54
d = 0*4
e = float("inf")
f = float("NaN")

print(math.isfinite(a))
print(math.isfinite(b))
print(math.isfinite(c))
print(math.isfinite(d))
print(math.isfinite(e))
print(math.isfinite(f))

``````

Output

``````
True
True
True
True
False
False

``````

### Example 2

Pass string as an argument in Python isfinite()
If we pass a string as an argument, then we should get an error.

``````# Importing math library
import math

print(math.isfinite('Nano'))

``````

Output

``````
python3 app.py
Traceback (most recent call last):
File "app.py", line 4, in <module>
print(math.isfinite('Nano'))
TypeError: must be real number, not str

``````

If we pass a string as an argument, then we got the TypeError.

### Example 3

Pass empty value as an argument
If we pass the empty values as an argument, then let’s see what we will get?

``````# Importing math library
import math

print(math.isfinite())

``````

Output

``````
Traceback (most recent call last):
File "app.py", line 4, in <module>
print(math.isfinite())
TypeError: isfinite() takes exactly one argument (0 given)

``````

So, we get: TypeError: isfinite() takes exactly one argument (0 given).

The function requires a minimum one argument, and if we don’t pass that, then we get TypeError.

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