Given a collection of intervals, merge all overlapping intervals.

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Given a collection of intervals, **merge * all *overlapping intervals**.

```
Input: [[1,3],[2,6],[8,10],[15,18]]
Output: [[1,6],[8,10],[15,18]]
Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into [1,6].
```

```
class Solution {
public int[][] merge(int[][] intervals) {
if (intervals.length == 0) {
return new int[0][0];
}
Arrays.sort(intervals, (i1, i2) -> i1[0] - i2[0]);
List<int[]> list = new ArrayList<>();
list.add(new int[] {intervals[0][0], intervals[0][1]});
for (int i = 1; i < intervals.length; i++) {
int[] lastItem = list.get(list.size() - 1);
if (intervals[i][0] > lastItem[1]) {
list.add(new int[] {intervals[i][0], intervals[i][1]});
} else if (intervals[i][1] > lastItem[1]) {
list.remove(list.size()-1);
list.add(new int[] {lastItem[0], intervals[i][1]});
}
}
int ans[][]= new int[list.size()][2];
for(int i=0; i< list.size(); i++)
{
int arr[] = list.get(i);
ans[i][0] = arr[0];
ans[i][1] = arr[1];
}
// int ans[] = new in[2][2];
return ans;
}
}
```

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