Avanya Shina

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Golang: How To Convert String to Byte Array Example

In Golang, to convert a string to byte array, you get a slice that contains the bytes of the string. In Go, a string is, in effect, a read-only slice of bytes. It’s essential to state right up front that a string holds arbitrary bytes. It is not required to hold Unicode text, UTF-8 text, or any other predefined format. As far as the content of a string is concerned, it is precisely equivalent to a slice of bytes.

#go #golang

What is GEEK

Buddha Community

Golang: How To Convert String to Byte Array Example
Neal  Bode

Neal Bode

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Golang Array Example | Arrays in Go Tutorial Explained

Golang array is a fixed-size collection of items of the same type. The items of an array are stored sequentially and can be accessed using their index. If we want to declare an array in Go, a programmer specifies the type of the elements and the number of items required by an array.

Golang array example

Golang programming language provides a data structure called an** array**, which can store the fixed-size sequential collection of items of the same type.

The array is used to store the collection of data, but it is often more useful to think of the array as the collection of variables of the same type.

Instead of declaring individual variables, such as no1, no2, …, and no99, you declare one array variable such as numbers and use no[0], no[1], and …, no[99] to represent individual variables.

#golang #go #golang array #golang programming

Madilyn  Kihn

Madilyn Kihn

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Convert String To Array Using Javascript Split Method

The easiest approach to use javascript built-in method String.split().

#javascript #javascript string #string to array #morioh #array

Joseph  Murray

Joseph Murray

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String Array In Java: Java String Array With Coding Examples

In Java, Array refers to a crucial data structure used to collect and store multiple data types from primitive to user-defined. String array is the array of various objects where each of its elements is a string. Users can perform several operations on these components, like adding a component, sorting, joining, searching, splitting, etc.

Introduction To A String Array In Java

It is possible to have an array with strings in Java as its derived elements. This means that users can define ‘String Array’ as an array that holds a certain number of string values or strings. In other words, it refers to a structure that is widely used in Java for having the string value. For instance, even the number of arguments of the prime function in Java refers to a string array.

#software development #array in java #java #string array

Avanya Shina

1597303320

Golang: How To Convert String to Byte Array Example

In Golang, to convert a string to byte array, you get a slice that contains the bytes of the string. In Go, a string is, in effect, a read-only slice of bytes. It’s essential to state right up front that a string holds arbitrary bytes. It is not required to hold Unicode text, UTF-8 text, or any other predefined format. As far as the content of a string is concerned, it is precisely equivalent to a slice of bytes.

#go #golang

Generate a string from an array of alphanumeric strings based on given conditions

Given an array of strings arr[] where each string is of the form “name:number” and a character T as input, the task is to generate a new string based on the following conditions:

  • In each string find the maximum digit in “number” which is less than or equal to the length of the string “name”.
  • If any such digit d is obtained, then append character at index d of the string name to the output string. Otherwise, append character T to the output string.

Examples:

Input:_ arr[] = {“Robert:36787”, “Tina:68721”, “Jo:56389”}, T = ‘X’_

Output:_ tiX_

Explanation:

For the first string “Robert:36787”: Length of “Robert” is 6. Since 6 is present in the string “36787”, 6th character of “Robert”, i.e. t is appended to the answer.

For the second string “Tina:68721”: Length of “Tina” is 4. The highest number less than equal to 4, which is present in “68721” is 2. Therefore, 2nd character of “Tina”, i.e. i is appended to the answer.

For the third string “Jo:56389”: Length of “Jo” is 2. Since no number less than equal to 2 is present in “56389”, T( = ‘X’) is appended to the answer.

Therefore, the final string after the above operations is “tiX”.

_Input: _arr[] = {“Geeks:89167”, “gfg:68795”}, T = ‘X’

Output:_ GX_

Explanation:

For the first string “Geeks:89167”, length of “Geeks” = 5 and the “89167” number has digit 1 which is less than 5.

So, the resultant string will have the character at the 1st position of the name, which is ‘G’.

For the second string “gfg:68795”, the length of “gfg” = 3, and the “68795” doesn’t have a digit less than or equals to 3.

So, the resultant string will have the character T.

Therefore, the final string after the above operations is “GX”.

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: To solve the problem follow the steps given below:

  1. Traverse through the array of strings and split each string around “:“. The first part contains the name and second part contains the number.
  2. Store the length of the name in a variable and find the maximum digit less than or equal to the length of number.
  3. If any such digit found is found, extract the character at that index of name and append to the resultant string. Otherwise, append T to the resultant string.
  4. Print the resultant string after repeating the above operations for all the strings in the array.

Below is the implementation of the above approach:

Java

// Java program for the above approach

**import** java.io.*;

**class** GFG {

// Function to generate required string

**public** **static** String

generatePassword(String s[], **char** T)

{

// To store the result

StringBuilder result

= **new** StringBuilder();

**for** (String currentString : s) {

// Split name and number

String person[]

= currentString.split(``":"``);

String name = person[``0``];

String number = person[``1``];

**int** n = name.length();

// Stores the maximum number

// less than or equal to the

// length of name

**int** max = 0``;

**for** (``**int** i = 0``;

i < number.length(); i++) {

// Check for number by parsing

// it to integer if it is greater

// than max number so far

**int** temp = Integer.parseInt(

String.valueOf(number.charAt(i)));

**if** (temp > max && temp <= n)

max = temp;

}

// Check if no such number is

// found then we append X

// to the result.

**if** (max == 0``)

result.append(T);

// Otherwise

**else**

// Append max index

// of the name

result.append(

String.valueOf(

name.charAt(max - 1``)));

}

// Return the final string

**return** result.toString();

}

// Driver Code

**public** **static** **void**

main(String[] args)

{

String arr[] = { "Geeks:89167"``,

"gfg:68795" };

**char** T = 'X'``;

// Function Call

System.out.println(

generatePassword(arr, T));

}

}

Output:

GX

Time Complexity:_ O(N)_

Auxiliary Space:_ O(1)_

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#arrays #searching #strings #strings