1624331609
Upload and display image using Python Flask and insert to PostgreSQL
install psycopg2 https://pypi.org/project/psycopg2/
Psycopg is the most popular PostgreSQL database adapter for the Python programming language.
(venv) PS C:\flaskmyproject> pip install psycopg2
CREATE TABLE upload (
id serial PRIMARY KEY,
title VARCHAR ( 100 ) NOT NULL,
);
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Source Code :
#app.py
from flask import Flask, flash, request, redirect, url_for, render_template
import urllib.request
import os
from werkzeug.utils import secure_filename
import psycopg2 #pip install psycopg2
import psycopg2.extras
app = Flask(__name__)
app.secret_key = "cairocoders-ednalan"
DB_HOST = "localhost"
DB_NAME = "sampledb"
DB_USER = "postgres"
DB_PASS = "admin"
conn = psycopg2.connect(dbname=DB_NAME, user=DB_USER, password=DB_PASS, host=DB_HOST)
UPLOAD_FOLDER = 'static/uploads/'
app.secret_key = "secret key"
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER
app.config['MAX_CONTENT_LENGTH'] = 16 * 1024 * 1024
ALLOWED_EXTENSIONS = set(['png', 'jpg', 'jpeg', 'gif'])
def allowed_file(filename):
return '.' in filename and filename.rsplit('.', 1)[1].lower() in ALLOWED_EXTENSIONS
@app.route('/')
def home():
return render_template('index.html')
@app.route('/', methods=['POST'])
def upload_image():
cursor = conn.cursor(cursor_factory=psycopg2.extras.DictCursor)
if 'file' not in request.files:
flash('No file part')
return redirect(request.url)
file = request.files['file']
if file.filename == '':
flash('No image selected for uploading')
return redirect(request.url)
if file and allowed_file(file.filename):
filename = secure_filename(file.filename)
file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))
#print('upload_image filename: ' + filename)
cursor.execute("INSERT INTO upload (title) VALUES (%s)", (filename,))
conn.commit()
flash('Image successfully uploaded and displayed below')
return render_template('index.html', filename=filename)
else:
flash('Allowed image types are - png, jpg, jpeg, gif')
return redirect(request.url)
@app.route('/display/<filename>')
def display_image(filename):
#print('display_image filename: ' + filename)
return redirect(url_for('static', filename='uploads/' + filename), code=301)
if __name__ == "__main__":
app.run()
templates/index.html
//templates/index.html
<html>
<head>
<title>Upload and display image using Python Flask and insert to PostgreSQL</title>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.0/jquery.min.js"></script>
</head>
<body>
<p><h1 align="center">Upload and display image using Python Flask and insert to PostgreSQL</h1></p>
<div class="container">
<div class="row">
<h2>Select a file to upload</h2>
<p>
{% with messages = get_flashed_messages() %}
{% if messages %}
<ul>
{% for message in messages %}
<li>{{ message }}</li>
{% endfor %}
</ul>
{% endif %}
{% endwith %}
</p>
{% if filename %}
<div>
<img src="{{ url_for('display_image', filename=filename) }}">
</div>
{% endif %}
<form method="post" action="/" enctype="multipart/form-data">
<dl>
<p>
<input type="file" name="file" class="form-control" autocomplete="off" required>
</p>
</dl>
<p>
<input type="submit" value="Submit" class="btn btn-info">
</p>
</form>
</div>
</div>
</body>
</html>
#python #postgresql #flask
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This laravel crop image before upload using cropper js looks like:
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Read More => https://www.tutsmake.com/laravel-crop-image-before-upload-using-jquery-copper-js/
Live Demo Laravel Crop image Before Upload.
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Setup Database Details
Generate Image Migration & Model
Create Image Upload Route
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https://www.tutsmake.com/laravel-7-6-image-upload-with-preview-validation-tutorial/
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#python #anonymous function python #filter function in python #lambda #lambda python 3 #map python #python filter #python filter lambda #python lambda #python lambda examples #python map