Riley Lambert

Riley Lambert


Getting undefined from jquery find() in my example

I have an HTML page like this :

I have put an event on input.global_filter using jquery as follows:

$('input.global_filter').on('keyup click', function() {
<script src=""></script>

<!-- Table3–>
<table class=“example” data-column=“3”>


<input type=“text” class=“global_filter”>

<!-- Table1–>
<table class=“example” data-column=“1”>


<!-- Table2–>
<table class=“example” data-column=“2”>


This results in undefined. It should give the result TABLE. Where am I wrong ?

#jquery #html

What is GEEK

Buddha Community

Tubo Man


In the above code you are using $(this) and when event get trigger this become the input field it means this keyword referring to input field, And then you are trying to find example:first inside the input field so you are getting undefined.

Check the following solution


Lyly Sara


please try with this:

   $('input.global_filter').on('keyup click', function() {

Watts Kendall


You have use parents instead of find. Try this:

  $('input.global_filter').on('keyup click', function() {

I am Developer


jQuery ajax get request method example

jQuery Ajax Get Request Method Example

This article is originally published at

Let’s see example of jquery ajax get request.

<html lang="en">
<meta charset="utf-8">
<title>jQuery Ajax GET Request Example</title>
<script src=""></script> 
    padding: 15px;
    border: 12px solid #23384E;
    background: #28BAA2;
    margin-top: 10px;
<script type="text/javascript">
    var name = "Tutsmake";
    $.get('', {webname: name}, function(data){
    <div class="formClass">
      <button type="button">Click &amp; Get Data</button><br>
      <div id="output">Hello</div>    
</html>   ```                         

This article is originally published at []( "")

#jquery #jquery ajax get request with parameters #ajax get method example #jquery ajax get request parameters #ajax

I am Developer


PHP jQuery Ajax Post Form Data Example

PHP jquery ajax POST request with MySQL. In this tutorial, you will learn how to create and submit a simple form in PHP using jQuery ajax post request. And how to submit a form data into MySQL database without the whole page refresh or reload. And also you will learn how to show an error message to the user if the user does not fill any form field.

And this tutorial also guide on how to send data to MySQL database using AJAX + jQuery + PHP without reloading the whole page and show a client-side validation error message if it has an error in the form.

PHP jQuery AJAX POST Form Data In Into MySQL DB Example

Just follow the few below steps and easily create and submit ajax form in PHP and MySQL with client-side validation.

  • Create Database And Table
  • Create a Database Connection File
  • Create An Ajax POST Form in PHP
  • Create An Ajax Data Store File

#jquery ajax serialize form data example #submit form using ajax in php example #save form data using ajax in php #how to insert form data using ajax in php #php jquery ajax form submit example #jquery ajax and jquery post form submit example with php

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How to Get Current URL in Laravel

In this small post we will see how to get current url in laravel, if you want to get current page url in laravel then we can use many method such type current(), full(), request(), url().

Here i will give you all example to get current page url in laravel, in this example i have used helper and function as well as so let’s start example of how to get current url id in laravel.

Read More : How to Get Current URL in Laravel

Read More : Laravel Signature Pad Example

#how to get current url in laravel #laravel get current url #get current page url in laravel #find current url in laravel #get full url in laravel #how to get current url id in laravel

Ray  Patel

Ray Patel


Get an SNS alert for High Severity GuardDuty findings with python

Get an SNS alert for High Severity GuardDuty findings

Problem: Getting notified when there is Red finding in AWS GuardDuty.

Functionality: Solution is to trigger the CloudWatch event and send SNS to user when there is any findings with severity of greater than 7 in Guardduty.

How to Run the Script : Create a Lambda function called “GuardDutyAlert” the run-time version Python 3.6 or above by using the attach code. Creation of the Lambda function will in turn create CloudWatch Logs groups for its logging. Lamda can be call every 5 mins or as per your business requirement.

#tool #python #sns alert #high severity guardduty findings #get an sns alert for high severity guardduty findings with python #get an sns alert for high severity guardduty findings