This week I’ll show another LeetCode question. I find it interesting how you can solve problems by reusing pieces of code that you already have. Last week I wrote about Removing Duplicates from a Sorted Array, I will re-use parts of the code I wrote last week to solve this challenge.
“Given an array nums and a value val, remove all instances of that value _**_in-place_ and return the new length. Do not allocate extra space for another array, you must do this by _modifying the input array _** **_in-place**_ with O(1) extra memory. The order of elements can be changed. It doesn’t matter what you leave beyond the new length.”_
Input: nums = [3,2,2,3], val = 3
Output: 2, nums = [2,2]
Explanation: Your function should return length = 2, with the first two elements of nums being 2.
It doesn’t matter what you leave beyond the returned length. For example if you return 2 with nums = [2,2,3,3] or nums = [2,2,0,0], your answer will be accepted.
In the previous post, I had to remove duplicate values from a sorted array and return its length, while in this task I just simply need to remove a given value from the array and return its length.
There are 2 steps of the algorithm that are the same:
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