int i = 3; int j = (i)++;
int i = 3;
int j = i ++;
Though both of the above examples store 3 in
j, is there a difference between how the above two cases are evaluated?
i is an
int, do the
() cause the first case to be evaluated as an expression, which would be equivalent to incrementing an rvalue? Or is it undefined behaviour and just happens to store 3 in
Or am I overthinking it and its just a simple postfix?
In this post, you'll see the difference between Rust and C/C++ in a developer’s perspective
ＬＩＫＥ | ＣＯＭＭＥＮＴ | ＳＨＡＲＥ | ＳＵＢＳＣＲＩＢＥ A variable is nothing but a name given to a storage area that our programs can manipulate. Each variable in C# has a speci...