Day 27 — Baseball Game

Day 27 — Baseball Game

100 Days to Amazon

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Hey Guys, Today is day 27 **of the challenge that I took. Wherein I will be solving every day for 100 days the [programming questions** ]( have been asked in** previous interviews.**

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All these problems are taken from the following [e-book_]( 🎓_

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This e-book contains 100 coding problems that have been asked in top tech interview questions. It also has a guide to solving all the problems in 200+ ways. **These problems I assure you** has been asked in previous interviews.

You have to decide whether you want to go** unprepared *for a tech interview or go ahead and **quick search for this guide *to solve the 100 problems.

Begin Your ascent to greatness

Day 27 — Baseball Game


You’re now a baseball game point recorder.

Given a list of strings, each string can be one of the 4 following types:

  1. Integer (one round's score): Directly represents the number of points you get in this round.
  2. "+" (one round's score): Represents that the points you get in this round are the sum of the last two valid round's points.
  3. "D" (one round's score): Represents that the points you get in this round are the doubled data of the last valid round's points.
  4. "C" (an operation, which isn't a round's score): Represents the last valid round's points you get were invalid and should be removed.

Each round’s operation is permanent and could have an impact on the round before and the round after.

You need to return the sum of the points you could get in all the rounds.


Input: ["5","2","C","D","+"]
Output: 30
Round 1: You could get 5 points. The sum is: 5.
Round 2: You could get 2 points. The sum is: 7.
Operation 1: The round 2's data was invalid. The sum is: 5\.  
Round 3: You could get 10 points (the round 2's data has been removed). The sum is: 15.
Round 4: You could get 5 + 10 = 15 points. The sum is: 30.


class Solution {
        public int calPoints(String[] ops) {
            Stack<Integer> s = new Stack();
        int res = 0;

            for(String str : ops) {
                if (str.equals("+")) {
                    int top = s.pop();
                    int newtop = top + s.peek();
                } else if (str.equals("C")) {
                } else if (str.equals("D")) {
                    s.push(2 * s.peek());
                } else {

            for(int total : s) res +=total;
            return res;

Author: Akshay Ravindran


  1. Create a *stack *that will store the values after each operation.
  2. If the value is C. It is just a *pop() *operation.
  3. If the value is an integer we have to push *that *value *into the *Stack.
  4. If the operation *is *D. We will get the top value of the stack and multiply it by two and push it into the stack.
  5. If the operation is +. Remove the top element add the current top with the previous top element.
  6. Push this new value *onto the *Stack.
  7. When you *reach *the end of the array, Traverse through the stack.
  8. Adding each value of the stack.
  9. *Return *the total 🔚

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