How to print the slice of pointers to get the values instead of their address without iteration at go?

This kind output required for debugging purpose. To get actual value of slice of pointers, every time a iteration is getting required.

Is there any way, we can directly have the value instead of the address of each item present at slice using simple fmt.printf()?

Here is a code snippet : https://play.golang.org/p/bQ5vWTlKZmV

package main
import (

“fmt”

)
type user struct {

userID int

name   string

email  string

}
func main() {

var users []*user

addUsers(users)

}
func addUsers(users []*user) {

users = append(users, &user{userID: 1, name: “cooluser1”, email: “cool.user1@gmail.com”})

users = append(users, &user{userID: 2, name: “cooluser2”, email: “cool.user2@gmail.com”})

printUsers(users)

printEachUser(users)
}
func printUsers(users []*user) {

fmt.Printf(“users at slice %v \n”, users)

}
func printEachUser(users []*user) {

for index, u := range users {

fmt.Printf(“user at user[%d] is : %v \n”, index, *u)

}

}

At above code, if I am printing the slice directly by fmt.printf , I get only the address of the values instead of actual value itself.

output : users at slice [0x442260 0x442280]

To read to the values always, i have to call func like printEachUser to iterate the slice and get the appropriate value .

output: user at user[0] is : {1 cooluser1 cool.user1@gmail.com} user at user[1] is : {2 cooluser2 cool.user2@gmail.com}

Is there any way, we can read the values inside the slice of pointers using fmt.printf and get value directly like below ?

users at slice [&{1 cooluser1 cool.user1@gmail.com} , &{2 cooluser2 cool.user2@gmail.com}]

#go