# C Program to Display Armstrong Numbers Between Two Intervals in C

To understand this example, you should have the knowledge of the following C programming topics:

• C if...else Statement
• C for Loop

A positive integer is called an Armstrong number (of order n) if

``````abcd... = an + bn + cn + dn +
``````

In the case of an Armstrong number of 3 digits, the sum of cubes of each digit is equal to the number itself. For example, 153 is an Armstrong number because

``````153 = 1*1*1 + 5*5*5 + 3*3*3
``````

In this program, we will print all the Armstrong numbers between two integers. This means that the two integers will not be part of the range, but only those integers that are between them.

For example, suppose we want to print all Armstrong numbers between 153 and 371. Both of these numbers are also Armstrong numbers.

Then, this program prints all Armstrong numbers that are greater than 153 and less than 371 i.e. 153 and 371 won't be printed even though they are Armstrong numbers

## Armstrong Numbers Between Two Integers

``````#include <math.h>
#include <stdio.h>
int main() {
int low, high, number, originalNumber, rem, count = 0;
double result = 0.0;
printf("Enter two numbers(intervals): ");
scanf("%d %d", &low, &high);
printf("Armstrong numbers between %d and %d are: ", low, high);

// swap numbers if high < low
if (high < low) {
high += low;
low = high - low;
high -= low;
}

// iterate number from (low + 1) to (high - 1)
// In each iteration, check if number is Armstrong
for (number = low + 1; number < high; ++number) {
originalNumber = number;

// number of digits calculation
while (originalNumber != 0) {
originalNumber /= 10;
++count;
}

originalNumber = number;

// result contains sum of nth power of individual digits
while (originalNumber != 0) {
rem = originalNumber % 10;
result += pow(rem, count);
originalNumber /= 10;
}

// check if number is equal to the sum of nth power of individual digits
if ((int)result == number) {
printf("%d ", number);
}

// resetting the values
count = 0;
result = 0;
}

return 0;
}``````

Run Code

Output

``````Enter two numbers(intervals): 200
2000
Armstrong numbers between 200 and 2000 are: 370 371 407 1634 ``````

In the program, the outer loop is iterated from (low+ 1) to (high - 1). In each iteration, it's checked whether number is an Armstrong number or not.

Inside the outer loop, the number of digits of an integer is calculated first and stored in `count`. And, the sum of the power of individual digits is stored in the result variable.

If number is equal to `result`, the number is an Armstrong number.

Notes:

• You need to swap low and high if the user input for high is less than that of low.
• You need to reset count and result to 0 in each iteration of the outer loop.

1.00 GEEK